Charles Law Problems Worksheet Answer Key: A Comprehensive Guide

Last Modified: Published: 2023/03
th?q=charles%20law%20problems%20worksheet%20answer%20key - Charles Law Problems Worksheet Answer Key: A Comprehensive Guide
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Introduction

Are you struggling to understand Charles Law problems and need a reliable answer key? Look no further! In this article, we will provide you with a comprehensive Charles Law problems worksheet answer key that will help you understand the concept and solve the problems with ease.

What is Charles Law?

Charles Law is a gas law that states that the volume of a given mass of gas at constant pressure is directly proportional to its absolute temperature. This law is named after the French scientist Jacques Charles, who first discovered it in 1787.

How to Solve Charles Law Problems?

To solve Charles Law problems, you need to use the following formula: V1/T1 = V2/T2 Where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Example Problem:

If a gas has an initial volume of 2.0 L at 25°C, what will be its volume at 50°C? Solution: V1 = 2.0 L T1 = 25 + 273 = 298 K T2 = 50 + 273 = 323 K V2 = (V1 x T2) / T1 V2 = (2.0 x 323) / 298 V2 = 2.17 L Therefore, the final volume of the gas is 2.17 L.

Charles Law Problems Worksheet Answer Key

1. If a gas has an initial volume of 5.0 L at 20°C, what will be its volume at 100°C? Solution: V1 = 5.0 L T1 = 20 + 273 = 293 K T2 = 100 + 273 = 373 K V2 = (V1 x T2) / T1 V2 = (5.0 x 373) / 293 V2 = 6.37 L Therefore, the final volume of the gas is 6.37 L. 2. If a gas has an initial volume of 2.5 L at 30°C, what will be its volume at 60°C? Solution: V1 = 2.5 L T1 = 30 + 273 = 303 K T2 = 60 + 273 = 333 K V2 = (V1 x T2) / T1 V2 = (2.5 x 333) / 303 V2 = 2.74 L Therefore, the final volume of the gas is 2.74 L. 3. If a gas has an initial volume of 10.0 L at 50°C, what will be its volume at 25°C? Solution: V1 = 10.0 L T1 = 50 + 273 = 323 K T2 = 25 + 273 = 298 K V2 = (V1 x T2) / T1 V2 = (10.0 x 298) / 323 V2 = 9.20 L Therefore, the final volume of the gas is 9.20 L. 4. If a gas has an initial volume of 3.0 L at 15°C, what will be its volume at 90°C? Solution: V1 = 3.0 L T1 = 15 + 273 = 288 K T2 = 90 + 273 = 363 K V2 = (V1 x T2) / T1 V2 = (3.0 x 363) / 288 V2 = 3.77 L Therefore, the final volume of the gas is 3.77 L.

Conclusion

Charles Law problems can be challenging, but with the help of this Charles Law problems worksheet answer key, you can solve them with ease. Remember to use the formula V1/T1 = V2/T2 and convert the temperature to Kelvin before applying it to the formula. Practice makes perfect, so keep practicing until you master the concept. Good luck!

 

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